Powers of 'P': Balancing a Helicopter at N Times the Scale

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    Helicopter Scale
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If the scale of the helicopter increases by a factor of n, its volume and mass will also increase proportionally to n^3, assuming constant density. Consequently, the power required to maintain equilibrium must also increase by the same factor, resulting in a new power of n^3P. The calculations provided confirm that as mass increases, the power needed to sustain flight must rise accordingly. The relationship between mass, power, and equilibrium is consistent with the principles of physics. Thus, the conclusion that the new power would be n^3P is correct.
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We have a helicopter flying and use the power "P" to keep it in equilibrium. But if the scale was greater n times, what would be the power to keep it there?
 
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Thanks, but didn't need such detail. I thought that if the scale was greater n times then the volume of the helicopter had to be proportional to n^3. So with the same density, its mass also had to be proportional to n^3.
<br /> P= \Delta W/t<br />

<br /> P=F \Delta x/t<br />

<br /> P=mg \Delta x/t<br />

So if m increases n^3 times, P must increase n^3 times and the new power would be n^3P.
Was I wrong?

for latex.
 
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