Prelab rotational motion question

AI Thread Summary
The discussion focuses on deriving equations related to a pulley system involving rotational motion and Newton's second law. The initial equation for the hanging mass is established as ma = mg - T. A substitution for linear acceleration is made using a = αr, linking angular and linear motion. The torque equation is expressed as τ = Tr, and ultimately combined to yield τ = m(g - αr)r, representing the torque exerted at the pulley rim. The solution appears valid, encouraging further reasoning about the equations' implications.
FlorenceC
Messages
24
Reaction score
0
There is an experimental set up that looks like the attitude file.
1) for mass hanging down the pulley write Newton's second law
2)since the sensor measures α find substitute a with a variable containing α
3) for the drum (horizontal pulley) find another equation for torque other than τ = Iα
4) combine eqn 1-3 to find an equation for τ via, T, a, r and α

The attempt at a solution
1) ma=mg-T
2) a = αr
3) τ = Tr
4) τ = m(g-αr) r
 

Attachments

  • img203.gif
    img203.gif
    3.1 KB · Views: 628
Physics news on Phys.org
That would be the torque exerted at the rim of the pulley by the hanging mass.
Looks OK to me - if you have doubts, try to reason through what the equations mean.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
13
Views
832
Replies
29
Views
4K
Replies
5
Views
3K
Replies
4
Views
13K
Replies
2
Views
2K
Replies
7
Views
3K
Replies
5
Views
2K
Replies
5
Views
5K
Replies
5
Views
1K
Back
Top