Pressure at Points: What Does the Bernoulli Equation Tell Us?

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Homework Help Overview

The discussion revolves around the application of the Bernoulli equation in fluid dynamics, specifically regarding the pressure at different points in a fluid system. Participants are exploring the relationship between pressures at two points and questioning the assumptions behind the equation's application.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to understand why pressures at two points in a fluid system are not equal and how the Bernoulli equation applies to this scenario. Questions about the significance of fluid velocity and height differences are raised, along with inquiries about the correct formulation of the Bernoulli equation.

Discussion Status

The discussion is ongoing, with participants providing insights into the Bernoulli equation and its implications. Some have offered clarifications on the terms used in the equation, while others are still seeking to understand the relationship between the pressures and the assumptions involved.

Contextual Notes

There are indications of confusion regarding the correct formulation of the Bernoulli equation and its application to specific points in the fluid system. Participants are encouraged to articulate their understanding of the equation and its terms, suggesting a need for further clarification on these concepts.

werson tan
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Homework Statement


isn't that p1 and [2 at the same point ? why shouldn't the P1 = P2 , which is
ρg(h1 +h2 +h3) ?

Homework Equations

The Attempt at a Solution

 

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The velocity of the liquid makes a difference! Bernoulli.
 
BvU said:
The velocity of the liquid makes a difference! Bernoulli.
can you explain further?
 
werson tan said:
can you explain further?
BvU means you must apply the Bernoulli equation to the two points to find out what the pressures are at those locations.

When the fluid is in motion, the pressure at any point is no longer equal to just the static pressure.
 
SteamKing said:
BvU means you must apply the Bernoulli equation to the two points to find out what the pressures are at those locations.

When the fluid is in motion, the pressure at any point is no longer equal to just the static pressure.
can you explain how to apply the Beroulli's pronciple so that the P1 = pg(h1 +h2) ? but not P1 = pg(h1 +h2+h3) ?
 
Have you learned about Bernoulli already ? This is a very straightforward application!
 
BvU said:
Have you learned about Bernoulli already ? This is a very straightforward application!
maybe there are some points that i have left out , can you point out please?
 
werson tan said:
maybe there are some points that i have left out , can you point out please?
Please write out the Bernoulli equation for us (if you know it)?
 
P +z + (v^2) /.2g , wher v = velocity
 
  • #10
werson tan said:
P +z + (v^2) /.2g , wher v = velocity
Please try again. This is not an equation. I know this, because I don't see an equal sign. I also don't see any density in the equation. None of the terms in the equation are dimensionally consistent with one another. Please look it up and get it right this time. Otherwise, you won't be able to solve your problem.
 
  • #11
Chestermiller said:
Please try again. This is not an equation. I know this, because I don't see an equal sign. I also don't see any density in the equation. None of the terms in the equation are dimensionally consistent with one another. Please look it up and get it right this time. Otherwise, you won't be able to solve your problem.
it should be P/ y + z + (v^2) /.2g , where v = velocity , y = ρg
 
  • #12
This is almost comical: 0084.png in post #1 says it all but apparently isn't acceptable for Werson. Do you find it difficult to understand the term with ##v^2## in the Bernoulli equation ?

(What Chet means is that this expression is a constant)
 
  • #13
werson tan said:
it should be P/ y + z + (v^2) /.2g , where v = velocity , y = ρg
This would be correct if that expression were set equal to a constant, and if that 0.2 in the denominator were a 2. Do you agree?
 
  • #14
Chestermiller said:
This would be correct if that expression were set equal to a constant, and if that 0.2 in the denominator were a 2. Do you agree?
how to relate it to the P1 ? why not P1 = P2 , which is ρg(h1 +h2 +h3) ?
 
  • #15
werson tan said:
how to relate it to the P1 ? why not P1 = P2 , which is ρg(h1 +h2 +h3) ?
Let's try to apply the Bernoulli equation to P1 and P2 to see what it tells us about their relationship. But, before doing that, do you understand the Bernoulli equation? Also, precisely what does z represent in the Bernoulli equation?
 
  • #16
Chestermiller said:
Let's try to apply the Bernoulli equation to P1 and P2 to see what it tells us about their relationship. But, before doing that, do you understand the Bernoulli equation? Also, precisely what does z represent in the Bernoulli equation?
z represent the difference in height between 2 points
 
  • #17
werson tan said:
z represent the difference in height between 2 points
You should think of z more as the elevation above a specified datum z = 0. In this problem, a logical choice for the datum would be the center of the pipe. Now please articulate what the Bernoulli equation means to you, or what each of the terms in the equation means physically.
 

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