Pressure Difference: U-Tube Manometer w/ 825kg/m^3 Fluid

  • Thread starter Thread starter Melawrghk
  • Start date Start date
  • Tags Tags
    U-tube
AI Thread Summary
To calculate the pressure difference in a U-tube manometer with a fluid density of 825 kg/m^3 and a height difference of 35 cm, the relevant formula involves the weight of the fluid column. The pressure difference can be determined by multiplying the fluid density by the height difference and the acceleration due to gravity. The area of the tube is irrelevant in this calculation since it cancels out. The pressure difference is effectively the weight of the fluid pressing down over a unit area. This approach simplifies the problem and leads to the correct pressure difference calculation.
Melawrghk
Messages
140
Reaction score
0

Homework Statement


A U-tube manometer contains a fluid with density of 825 kg/m^3. The difference in height of the two columns is 35cm. What is the pressure difference?

Homework Equations


None?

The Attempt at a Solution


I have no bloody clue. I'm sure I've done this before in AP Chem, but right now... I'm clueless. I think its something really simple, too.
Edit: Now that I think of it... the time variable in P=m/(A*t^2) doesn't change (there is no delta t), so density of the liquid multiplied by the difference in height squared would give me the difference in pressure. Am I even close to the truth?
 
Last edited:
Physics news on Phys.org
Pressure is force / area , or weight / area if you prefer.
You don't need the area of the tube since this cancels out, but if you prefer you can think of it as 1m^2.
Now just work out the weight of the extra 35cm * 1m^1 of fluid.
This is the weight pressing down on 1m^2 = pressure (watch the units)
 
Back
Top