Pressure in a container placed on a reduced area?

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In a closed container with a uniform pressure of 1 Pascal, the pressure remains constant throughout, regardless of the area measured. When calculating force on a smaller area, such as 1 mm², the force can be determined using the formula F = P * A, where P is the pressure and A is the area. Thus, the force exerted on the smaller area will be less than that on a larger area, but the pressure itself does not increase. The analogy of a hammer versus a blunt object illustrates how pressure can lead to different force applications based on area. Overall, the pressure inside the container remains 1 Pascal, confirming that pressure is uniform in a closed system.
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Really simple question but it's been making me a little confused.

Lets imagine we have a container (cubic with length of 1 meter) with a pressure of 1 Pascal and then an area inside the container of 1 mm^2 is chosen to measure the force on that area, what would the pressure be? 1 Pascal or 1000 Pascals?

My guess is the gas pressure applied to the smaller area would be larger than the pressure on the walls of the entire container similar to how a hammer can put a nail in wood easier than a blunt object.
 
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If the container is closed and has an internal pressure of 1 pascal, then the pressure everywhere inside the container is the same: 1 pascal.

Now, the equivalent force over a certain area in the container will change, since the pressure P = F / A. P is a constant, but A can be chosen as 1 cm2, or 1 mm2 or whatever, and F can be calculated by F = P * A.
 
SteamKing said:
F can be calculated by F = P * A.
Thanks! now it makes sense.
 
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