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## Main Question or Discussion Point

what would the pressure of liquid at a depth be in a container which is slanted?

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- #1

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what would the pressure of liquid at a depth be in a container which is slanted?

- #2

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i suspect [tex] h.d.g.sinAngle [/tex]. correct me if i am wrong

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russ_watters

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russ_watters

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Gravity pulls straight down, so...

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of course but i find similar case to the inclined plane. can somebody give a reasoning?

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russ_watters

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What do you find similar about an inclined plane? What is YOUR reasoning?

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somebody reply

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Doc Al

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If you want more, give a specific example of what you have in mind with a diagram.

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russ_watters

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wouldnt this imply that the liquid would accelerate at g in slanted tubes?

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Doc Al

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No. Please describe exactly what you have in mind. Are you talking about hydrostatic pressure? (Which is what I assumed.) Or fluid dynamics?wouldnt this imply that the liquid would accelerate at g in slanted tubes?

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russ_watters

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- #14

DaveC426913

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Since you're talking about pressure-at-depth then you're talking about a containerwouldnt this imply that the liquid would accelerate at g in slanted tubes?

Water suspended in water is neutrally buoyant, so its not like some arbitrary mass of water is going to start sliding to the bottom, accelerating under gravity.

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I am not familiar with the terms but i guess you are asking whether i am talking about stationary fluids or flowing ones. Eg. in an inclined plane, there is a mass a top, even though its weight acts exactly downward, it would rather move along the plane. And the force with with it moves along the plane is lesser according to its slope. Same for liquids. But as dave said while the liquid is continuous and stationary, the force with with a finite upper part of liquid exerts on the lower part will be the same as for the case of liquids in vertical column. This is not clear to me.

Eg. lets take a column of liquid standing upright and pour some water into it. And then slant it a bit. Then the depth of the liquid increases even though it is not continuous on the upper part (i hope this is understood). So as the depth increases although not uniformly, the pressure in one side must increase. Help me out with this.

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Another set:

Notice that no matter how weird the shape, the tops of the liquid surfaces in the different containers are at the same level. The pressure difference in some container from bottom to top does not depend on shape. It depends only the height of the liquid.

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russ_watters

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This is getting very frustrating for me because a bunch of people are putting a bunch of effort into helping you learn, but it doesn't seem like you are trying at all. For example, you said you don't know terms like "hydrostatic", but that term is defined in the very first sentence of the link i gave you in the first reply!i havent learned any of hydrodynamics or hydrostatics.

"Learning" is not something we can give you: we can tell you where to find the knowledge, but you have to get it into your head.

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OP , when I was a kid (well now also I am a kid in class 10th ! ) I also used to think the same way as you are currently.i suspect [tex] h.d.g.sinAngle [/tex]. correct me if i am wrong

I used to say :

Pressure = (Force x sin θ)/Area

Now I know that I was wrong because - Pressure is "thrust upon area." It is defined this way. Thrust is defined as force acting perpendicularly on a body.

Hence always ,

P=hρg x sin 90

As sin 90

So P=hρg

Do you get it now ?

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take a glass of water, then slant it slightly so as not to drop the water, As the depth increases on one side, doesent the pressure increase?

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- #23

Doc Al

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Yes. Pressure depends on the vertical distance below the fluid surface. Shape of the container has nothing to do with it.

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So to find out whether or not the pressure will increase, you will have to calculate the water level when straight and the water level when slanted. Then you can compare these to find the pressure difference.

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thank u chingel, thats what i wanted.

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