Pressure on a lateral side of a tank

[Misr]

You mean that i should first find the force that one coin exerts,then the force that all other coins exert and add them to the force of the chess board :!
so the force on the table=(64*100)+force of the chess board

So pressure on the table=6400+force of the chess board/area(I guess area=640)

 

[Misr]

Well,okay,may be you mean that force is still the same whatever the way we distribute it.