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Pressure -- open a window on a box

  1. Jul 17, 2014 #1
    1. The problem statement, all variables and given/known data

    if i have a box of:
    volume V1= 2 m3
    pressure p1= 0.5 KPa
    temperature T1= 80° C
    with a window of A=0.2 m2

    if i open the window what is the time for pressure box= pressure atmosphere?
    temperature atmosphere T2= 25°C
    pressure atmosphere P2=101kPa

    2. Relevant equations

    Q=V3/time [m3/sec]
    V3 volume air goes inside the box

    V1p1=V3p3=V3p2
    V3=(V1p1)/p2
    them
    time=V3/Q=(V1p1)/(p2Q)

    but Q? i don't understand
     
  2. jcsd
  3. Jul 17, 2014 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    Hi opsops. Welcome to Physics Forums. :wink:

    That is an interesting question you have. You made it up, did you? :smile:
     
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