Pressure: how much force is needed on the small piston to lift the car? 1. The problem statement, all variables and given/known data A hydrolic piston with a radius of 1 inch is connected with a hose to a piston with a radius of 5 inches. There is 1000 kg (9800N) car sitting on top of the large piston. How much force is needed on the small piston to lift the car? 2. Relevant equations 14.7 psi = lb/in^2 circumference = 2 x 3.14 x radius Area of a circle = 3.14 x radius^2 lbs / in^2 P = F / A F = PA I'm guessing... these are somewhat my formulas. 3. The attempt at a solution So far, this is what I attempted, but I'm pretty sure it's not correct because it is very rare I am right. 1000 kg/ (3.14 x 5^2 in^2) = 7957.7 psi 7957.7 psi x 3.14 = 24999.9 lbs Plus, I think I should use 9800N at least sometime in this problem. Please tell me what I should change and what steps I should take. And then help me figure the Ideal Mechanical Advantage (I. M. A.) of the hydraulic system?