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**Pressure: how much force is needed on the small piston to lift the car?**

## Homework Statement

A hydrolic piston with a radius of 1 inch is connected with a hose to a piston with a radius of 5 inches. There is 1000 kg (9800N) car sitting on top of the large piston. How much force is needed on the small piston to lift the car?

## Homework Equations

14.7 psi = lb/in^2

circumference = 2 x 3.14 x radius

Area of a circle = 3.14 x radius^2

lbs / in^2

P = F / A

F = PA

I'm guessing... these are somewhat my formulas.

## The Attempt at a Solution

So far, this is what I attempted, but I'm pretty sure it's not correct because it is very rare I am right.

1000 kg/ (3.14 x 5^2 in^2) = 7957.7 psi

7957.7 psi x 3.14 = 24999.9 lbs

Plus, I think I should use 9800N at least sometime in this problem. Please tell me what I should change and what steps I should take. And then help me figure the Ideal Mechanical Advantage (I. M. A.) of the hydraulic system?

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