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Pressure: how much force is needed on the small piston to lift the car?
A hydrolic piston with a radius of 1 inch is connected with a hose to a piston with a radius of 5 inches. There is 1000 kg (9800N) car sitting on top of the large piston. How much force is needed on the small piston to lift the car?
14.7 psi = lb/in^2
circumference = 2 x 3.14 x radius
Area of a circle = 3.14 x radius^2
lbs / in^2
P = F / A
F = PA
I'm guessing... these are somewhat my formulas.
So far, this is what I attempted, but I'm pretty sure it's not correct because it is very rare I am right.
1000 kg/ (3.14 x 5^2 in^2) = 7957.7 psi
7957.7 psi x 3.14 = 24999.9 lbs
Plus, I think I should use 9800N at least sometime in this problem. Please tell me what I should change and what steps I should take. And then help me figure the Ideal Mechanical Advantage (I. M. A.) of the hydraulic system?
Homework Statement
A hydrolic piston with a radius of 1 inch is connected with a hose to a piston with a radius of 5 inches. There is 1000 kg (9800N) car sitting on top of the large piston. How much force is needed on the small piston to lift the car?
Homework Equations
14.7 psi = lb/in^2
circumference = 2 x 3.14 x radius
Area of a circle = 3.14 x radius^2
lbs / in^2
P = F / A
F = PA
I'm guessing... these are somewhat my formulas.
The Attempt at a Solution
So far, this is what I attempted, but I'm pretty sure it's not correct because it is very rare I am right.
1000 kg/ (3.14 x 5^2 in^2) = 7957.7 psi
7957.7 psi x 3.14 = 24999.9 lbs
Plus, I think I should use 9800N at least sometime in this problem. Please tell me what I should change and what steps I should take. And then help me figure the Ideal Mechanical Advantage (I. M. A.) of the hydraulic system?
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