How Can Torque and Tension Prevent Building Collapse?

In summary, the conversation discusses the concept of torque and forces on a symmetric building with a sloping roof. The discussion involves calculating the horizontal force exerted by the roof on the top of the wall, the danger of collapsing for buildings with tall walls, and the use of flying buttresses to counteract the outward force on the walls. The force of the roof is not only acting in the vertical direction due to gravity, but also has components in the horizontal direction, which can be determined using the angle of the roof. The flying buttresses were used to counterbalance this outward force on the top of the walls, rather than applying torque to the roof itself.
  • #1
asleight
152
0

Homework Statement



A symmetric building has a roof sloping upward at [tex]36.0^\circ[/tex] above the horizontal on each side.

(a) If each side of the uniform roof weighs [tex]1.10\times10^4[/tex]N, find the horizontal force that this roof exerts at the top of the wall, which tends to push out the walls.

(b) Which type of building would be more in danger of collapsing: one with tall walls or one with short walls? Explain.

(c) As you saw in part (a), tall walls are in danger of collapsing from the weight of the roof. This problem plagued the ancient builders of large structures. A solution used in the great Gothic cathedrals during the 1200s was the flying buttress, a stone support running between the walls and the ground that helped to hold in the walls. A Gothic church has a uniform roof weighing a total of [tex]20000[/tex]N and rising at [tex]40.0^\circ[/tex] above the horizontal at each wall. The walls are [tex]40[/tex]m tall, and a flying buttress meets each wall [tex]10[/tex]m below the base of the roof. What horizontal force must this flying buttress apply to the wall?

Homework Equations



[tex]\sum\vec{F}=m\vec{a}[/tex]

[tex]\sum\vec{\tau}=I\vec{a}=\sum\vec{r}_i\times\vec{F}_i[/tex]

The Attempt at a Solution



For part (a), I can't see how any force is being applied in the x-direction, rather than just in the y-direction, caused by the force due to gravity. Once this force is recognized, I can solve for the torque about the base of the walls but I don't see how the force applied isn't parallel to the lever arm.

For part (b), it's given and intuitive that tall walls are more subject to falling due to a longer lever arm and, consequently, a greater net torque, driving the system out of equilibrium.

For part (c), I'd choose the axis of rotation to be about one of the walls with a torque in the positive direction caused by the Flying Buttress and a torque in the negative direction applied by the roof. From there, however, I can't seem to see this system in its true, physical light.

Enlighten me?
 
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  • #2
asleight said:
For part (a), I can't see how any force is being applied in the x-direction, rather than just in the y-direction, caused by the force due to gravity. Once this force is recognized, I can solve for the torque about the base of the walls but I don't see how the force applied isn't parallel to the lever arm.
Hint: Consider the force that one side exerts on the other where they meet at the top. What direction must that force be in?
 
  • #3
Doc Al said:
Hint: Consider the force that one side exerts on the other where they meet at the top. What direction must that force be in?

I don't understand this either. I know that the two parts of the roof connect and impose some kind of frictional force due to gravity but I don't know why they don't just fall. I don't see why the axis of rotation isn't the center of mass with no external torques acting upon the roof component to drive it to push outward on the wall or against the other side of the roof.
 
  • #4
asleight said:
I don't understand this either. I know that the two parts of the roof connect and impose some kind of frictional force due to gravity but I don't know why they don't just fall. I don't see why the axis of rotation isn't the center of mass with no external torques acting upon the roof component to drive it to push outward on the wall or against the other side of the roof.

Where the peak of the roof meets the weight of the roof will press one side against the other. Since that total weight translates down to the top of the wall there is a force vector that has both an x and y component at the top support on the wall. The y component is carried vertically to ground and hence there is only the compressional forces to deal with bearing the weight.

However there are horizontal forces acting at the top of the wall, that comes from bearing the roof. These component forces will be determined by the angle given by the roof.

So which wall - shorter or taller will be able to withstand this outward force?
(Hint: Ever seen pictures of Notre Dame in Paris?)
 
  • #5
LowlyPion said:
Where the peak of the roof meets the weight of the roof will press one side against the other. Since that total weight translates down to the top of the wall there is a force vector that has both an x and y component at the top support on the wall. The y component is carried vertically to ground and hence there is only the compressional forces to deal with bearing the weight.

However there are horizontal forces acting at the top of the wall, that comes from bearing the roof. These component forces will be determined by the angle given by the roof.

So which wall - shorter or taller will be able to withstand this outward force?

The shorter one can withstand the outward force better; but, I only understand this conceptually. The middle-ground seems obscure and abstract to me.
 
  • #6
asleight said:
The shorter one can withstand the outward force better; but, I only understand this conceptually. The middle-ground seems obscure and abstract to me.

The purpose of the flying buttress was not to apply torque to the roof. It was to apply counterbalancing torque to the top of the wall.

The force of the roof is a vector.

Look at the x,y components of the force at 36 degrees to determine the outward force.
 
  • #7
LowlyPion said:
The purpose of the flying buttress was not to apply torque to the roof. It was to apply counterbalancing torque to the top of the wall.

The force of the roof is a vector.

Look at the x,y components of the force at 36 degrees to determine the outward force.

I see the vector but WHY does it have x- and y-components? Why isn't it just the weight acting upon the center of mass, like I've been taught?
 
  • #8
Looking at it, I solved for the weight acting along the roof's axis, giving [tex]\vec{w}\sin(36\pi/180)[/tex]. Then, because this weight force acts non-orthogonally against the wall, we have to solve for the horizontal component of this weight, giving [tex]\vec{w}\sin(36\pi/180)\cos(36pi/180)[/tex]. This doesn't work. My trig.'s right for what I'm trying to set-up, but obviously my set-up is incorrect.
 
  • #9
What's wrong with my work? :/
 

What is pressure and how is it measured?

Pressure is the amount of force exerted on a surface divided by the area of that surface. It is typically measured in units of pressure, such as pounds per square inch (psi) or pascals (Pa).

What is tension and how is it related to pressure?

Tension is the force exerted on an object that is being pulled or stretched. It is related to pressure in that an increase in tension can cause an increase in pressure on the object being pulled or stretched.

What is torque and how is it different from pressure and tension?

Torque is a measure of the twisting force on an object. It is different from pressure and tension in that it is a rotational force, whereas pressure and tension are linear forces.

What are some real-world applications of pressure, tension, and torque?

Pressure is important in various fields such as engineering, meteorology, and medicine. Tension is important in structures and machines, as well as in the human body for functions like muscle movement. Torque is used in engines, machines, and tools, as well as in sports like baseball and golf.

How can pressure, tension, and torque be calculated or measured in an experiment?

To calculate or measure pressure, one can use a pressure gauge or manometer. Tension can be calculated using the force applied and the cross-sectional area of the object. Torque can be measured using a torque wrench or calculated using the force applied and the distance from the pivot point.

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