Pressure Vessels: Radial & Hoop Stresses at Inner & Outer Surfaces

  • Thread starter Thread starter tone999
  • Start date Start date
  • Tags Tags
    Pressure
AI Thread Summary
The discussion focuses on calculating the radial and hoop stresses for a cylinder subjected to internal pressure. The cylinder has an internal diameter of 30mm and an external diameter of 50mm, with an internal pressure of 60MPa. Participants clarify that "r" in the equations refers to the radius at a specific point within the cylinder, which is essential for accurate calculations. It is emphasized that consistent units must be used, converting measurements from millimeters to meters. The thread seeks confirmation on the correctness of the provided equations and guidance on how to proceed with the calculations.
tone999
Messages
17
Reaction score
0

Homework Statement


A cylinder has an internal diameter of 30mm and an external diameter of 50mm and is subject to an internal pressure which is 60MPa above that in the air surrounding the cylinder. Determine the radial and hoop stresses at the inner and outer surfaces.

Homework Equations


Basically i know:
internal radius in know as r1
external radius is r2

radial stress: pr1 squared/r2squared-r1squared X (r squared - r2 squared/ r squared)

hoop stresses : pr1 squared/r2squared-r1squared X (r squared + r2 squared/ r squared)

I don't know if these two equations are correct hopefully somebody could clarify this for me because the working out should be simple when this is known.

The Attempt at a Solution


I don't know what "r" is?
If i knew that i could take a stab at the equations hopefully somebody could give me two answers and if the equations are correct and two answers and i will do it myself to check this. Thanks
 
Physics news on Phys.org
tone999 said:
I don't know what "r" is?

Radius is half the diameter, which would be 15mm and 25mm. I don't know if your formula is correct but make sure you keep the units consistent; I think MPa requires that you work in meters (m), not milimeters (mm).
 
Yeah I've got that. I mean "r" on its own in the equation. I know the values for r1 - 0.015m
r2 - 0.025m
Internal pressure - 60x10 to the power of 6 Nm2
 
Thread 'Have I solved this structural engineering equation correctly?'
Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
Back
Top