(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

1) Find the area under the curve for:

a) P( 0 <= Z <= 2.07)

b) P(-.64 <= Z < -.11)

c) P( Z > -1.06)

d) P(Z < -2.33)

e) P(Z >= 4.61)

2) a) Evaluate integral from 0 to 1.24 of e^(-x^2/2)

b) Evaluate the integral from -inf to inf of 6*e^(-x^2/2)

2. Relevant equations

Z value table

Power series expansion of e^x

3. The attempt at a solution

1)

a) Fz(2.07) - Fz(0) = .9808 - .5 = .4808

b) Fz(-.64) - Fz(a) = .4247 - .2611 = .163

c) 1 - Fz(-1.06) = .85

d) .0104

e) .00002

Can someone explain to me the difference in calculating an area where Z < x vs. Z <= x. Do I just use the value closest to x and less than it on the table for Z < x?

2) a)I used the power series expansion and dervied each term upto n = 4 and got

.6807

b) No clue how to do this. Polar coordinates?

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# Homework Help: Probability and gauss integral

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