Probability of <3 Errors in 10-char Msg

AI Thread Summary
The discussion focuses on calculating the probability of encountering less than 3 errors in a 10-character message, where each character has a 1/10 chance of being erroneous. The binomial formula is applied correctly, using n = 10, p = 1/10, and summing the probabilities for k = 0, 1, and 2 errors. Participants confirm that the approach is valid, emphasizing the importance of accurate arithmetic in the calculations. The conversation reassures that the method used is appropriate for solving the problem. Overall, the probability of less than 3 errors is derived using the binomial distribution.
magnifik
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In sending 10 characters, a character error occurs independently with probability 1/10. What is the probability that in a 10-character message, less than 3 errors occur?

I am using the binomial formula (n choose k)pk(1-p)n-k where n = 10, p = 1/10, and k is the number of errors. Since the problem statement says less than 3 errors occur, I adding up the values for k = 0, 1, 2

(10 choose 0)(1/10)0(1-1/10)10 + (10 choose 1)(1/10)1(1-1/10)9 + (10 choose 2)(1/10)2(1-1/10)8, but i am wondering if I am doing this correctly? should i be adding or multiplying?
 
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magnifik said:
In sending 10 characters, a character error occurs independently with probability 1/10. What is the probability that in a 10-character message, less than 3 errors occur?

I am using the binomial formula (n choose k)pk(1-p)n-k where n = 10, p = 1/10, and k is the number of errors. Since the problem statement says less than 3 errors occur, I adding up the values for k = 0, 1, 2

(10 choose 0)(1/10)0(1-1/10)10 + (10 choose 1)(1/10)1(1-1/10)9 + (10 choose 2)(1/10)2(1-1/10)8, but i am wondering if I am doing this correctly?

You have written everything correctly, so if you have not made any arithmetical errors your answer should be correct.

RGV
 
thanks
 
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