Probability of Getting Head or 4: 7/12

  • Thread starter Thread starter alijan kk
  • Start date Start date
  • Tags Tags
    Probability
AI Thread Summary
The probability of getting a head or a 4 when flipping a coin and rolling a die is calculated by considering the sample space, which includes all combinations of coin flips and die rolls. The relevant events are identified as getting a head (H) or rolling a 4, leading to a total of 7 favorable outcomes out of 12 possible outcomes. The formula for calculating the probability of either event occurring is clarified, emphasizing that "or" includes the possibility of both events happening. It is important to include the event (H, 4) in the calculations to accurately determine the probability. The final probability is confirmed to be 7/12.
alijan kk
Messages
130
Reaction score
5

Homework Statement


If a coin flipped and one die is thrown, what is the probability of getting a head or a 4 ?

Homework Equations

The Attempt at a Solution


Sample Space={ H,1 H,2 H,3 H,4 H,5 H,6 T,1 T,2 T,3 T,4 T,5 T,6 }
Event={ H,1 H,2 H,3 H,5 H,6 T,4 }
probability is 6/12

if i don't do it with the formula P(A)+P(B)-P(AintersectionB)

i know the probability is 7/12

but what does probability of " a head or a 4" really mean ? should i add H,4 in the set of event but why it is necessary if yes
 
Physics news on Phys.org
alijan kk said:

Homework Statement


If a coin flipped and one die is thrown, what is the probability of getting a head or a 4 ?

Homework Equations

The Attempt at a Solution


Sample Space={ H,1 H,2 H,3 H,4 H,5 H,6 T,1 T,2 T,3 T,4 T,5 T,6 }
Event={ H,1 H,2 H,3 H,5 H,6 T,4 }
You left out the event H, 4.
alijan kk said:
probability is 6/12

if i don't do it with the formula P(A)+P(B)-P(AintersectionB)

i know the probability is 7/12

but what does probability of " a head or a 4" really mean ? should i add H,4 in the set of event but why it is necessary if yes

From the other thread you started (now deleted):
alijan kk said:
but what does probability of " a head or a 4" really mean ? should i add H,4 in the set of event but why it is necessary if yes
Yes you should add H, 4 to the events you're looking at. "A head or a 4" means that the coin turned up with a head OR the 4 on the die was on top OR both.
 
Mark44 said:
You left out the event H, 4.
H or 4 does that not mean either H or either 4 ? what is the difference in " H and 4 "
 
alijan kk said:
H or 4 does that not mean either H or either 4 ? what is the difference in " H and 4 "
No, "or" here does not mean "either H or 4." It includes the possibility of both occurring.
So P(H or 4) consists of the events {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 4)}.
P(H and 4) consists of only one event: {(H, 4}}.
 
  • Like
Likes alijan kk
Mark44 said:
No, "or" here does not mean "either H or 4." It includes the possibility of both occurring.
So P(H or 4) consists of the events {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 4)}.
P(H and 4) consists of only one event: {(H, 4}}.
Thanks again <3
 
but what does probability of " a head or a 4" really mean ?
Don't get confuse .Be clear with event.
P (AUB) = P (A)+P (B)- P (A intersection B)
Use this formula if A intersects B.

P (AUB) = P (A)+P (B) => use this formula if A does not intersect B.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top