Probability (probability mass function,pmf)

  • Thread starter Thread starter naspek
  • Start date Start date
  • Tags Tags
    Mass Probability
naspek
Messages
176
Reaction score
0
If X has the probability mass function f(x) = k / x! (x=0,1,2,...),
what is the value of k?
 
Physics news on Phys.org
I think you mean "probability density function".

The total probability must be 1.
\sum_{x=0}^\infty k/x!= k\sum_{x=0}^\infty 1/x!= 1

Do you know what that sum is?
 
HallsofIvy said:
I think you mean "probability density function".

The total probability must be 1.
\sum_{x=0}^\infty k/x!= k\sum_{x=0}^\infty 1/x!= 1

Do you know what that sum is?
i don't know.. is it infinity?
 
For discrete distributions these are usually called mass functions - density is reserved for continuous distributions.

naspek, HallsofIvy is asking whether you can identify what the sum

<br /> \sum_{x=0}^\infty \frac 1 {x!}<br />

equals? This problem should remind you of a commonly used distribution.
 
You probably have not taken calculus yet, but if you had you would have learned that
e^x= \sum_{n=0}^\infty \frac{x^n}{n!}.

Do you know what an "exponential probability distribution" is?
 
Last edited by a moderator:
HallsofIvy said:
You probably have not taken calculus yet, but if you had you would have learned that
e^x= \sum_{n=0}&amp;\infty \frac{x^n}{n!}.

Do you know what an "exponential probability distribution" is?

ok.. now i understand already... thanks guys! =)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top