Probability Problem: At Least 1 Grow, At Least 1 Not Grow

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SUMMARY

The probability problem involves determining the likelihood of at least one flower growing and at least one not growing when planting four seeds, each with a 90% growth probability. The calculated probabilities are 0.6561 for all seeds growing and 0.0001 for none growing. The equation established is P(0) + P(1 ≤ n ≤ 3) + P(4) = 1, where P(0) and P(4) are known, allowing for the calculation of P(1 ≤ n ≤ 3).

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Yankel
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Hello all,

I am stuck with this one, it looks simple but yet confusing. Can you assist please ?

The probability of a flower to grow is 0.9. We put in the ground 4 seeds of this flower. What is the probability that at least
one will grow and at least one will not grow ?

Thank you.
 
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We know:

It is certain that none will grow OR At least 1 will grow and 1 will not grow OR all will grow.

What are the probabilities that none will grow, and that all will grow?
 
probability that all will grow is 0.6561 and that none will grow 0.0001, right ?

Now what ?
 
Yankel said:
probability that all will grow is 0.6561 and that none will grow 0.0001, right ?

Now what ?

Yes, that's correct. :D

So now we want to take this:

It is certain that none will grow OR At least 1 will grow and 1 will not grow OR all will grow

and turn it into an equation. If we let $n$ be the number that grows we may write:

$$P(0)+P(1\le n\le3)+P(4)=1$$

You have already correctly determined $P(0)$ and $P(4)$, and so it is now just a matter of solving for $P(1\le n\le3)$, which is what we are trying to find. :)
 
Oh...when you put it like this... :D

Thanks !
 

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