Probability problem of pairing up siblings

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The discussion focuses on calculating the expected values E(X) and E(Y) for randomly pairing 10 sister/brother pairs into 10 pairs. Participants suggest using combinatorial methods to determine the number of ways to form pairs and to find probabilities for specific configurations of male/female and sibling pairs. The importance of expressing random variables in terms of indicator variables is emphasized, particularly for calculating expected values. A suggestion is made to consider different cases of pairing based on the number of males and females involved. Overall, the conversation highlights the complexity of the problem and the utility of statistical approaches in finding solutions.
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Homework Statement



There are 10 sister/brother pairs, (S1,B1) ... , (S10,B10). We then divide the 20 people randomly into 10 (not necessarily female/male) pairs.

Let X be the number of female/male pairs. Find E(X)
Let Y be the number of pairs consisting of siblings (that is, sister got matched with her brother). Find E(Y)


Homework Equations





The Attempt at a Solution



I only know how to find out the total number of ways to select 10 pairs, that's (20,2)+(18,2)+(16,2)+...+(2,2). (x,y) means x choose y

Please help. Thanks!
 
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Firstly notice whether you can have odd number of bro - sis pairs. What would be the probability of odd x then?

Now going to even x. For example let's take x = 2. How many ways of selecting two bro - sis pairs exist? Clearly to make a pair you need to choose 1 bro and 1 sis out of 10 each. For the next pair, 1 bro and i sis out of 9 each. Then you just need to pair up 8 boys and 8 girls into boy-boy and girl-girl pairs.

Calculate that and then divide by the total number of ways of pairing the 20 siblings. This will give you p(x=2). You can similarly find p(x) for other even x.
 
It's often much easier to find the expectation of a random variable than all the probabilities,
because E(X+Y) = E(X) + E(Y) always.

suppose X_i is 1 if sibling i is member of a pair, and 0 otherwise, what is E(X_i) ?

Now find the expected value of the total of pair-memberships, and find the number of pairs from that.

The second problem can be done in the same way.
 
willem2 said:
It's often much easier to find the expectation of a random variable than all the probabilities,
because E(X+Y) = E(X) + E(Y) always.

suppose X_i is 1 if sibling i is member of a pair, and 0 otherwise, what is E(X_i) ?

Now find the expected value of the total of pair-memberships, and find the number of pairs from that.

The second problem can be done in the same way.

When you say Xi is 1 if sibling is member of a pair, do you mean a pair of opposite sex? And does it mean both bro and sis in ith pair got assigned to another pair of opposite sex?
 
ilvpat said:
When you say Xi is 1 if sibling is member of a pair, do you mean a pair of opposite sex? And does it mean both bro and sis in ith pair got assigned to another pair of opposite sex?

For i = 1,2,..., 10, let ##I_i = 1## if sister S_i is paired with a boy, and ##I_i = 0## otherwise; and let ##J_i = 1## if sister S_i is paired with her brother, and let ##J_i = 0## otherwise. Try to express X and Y in terms of the ##I_i## and/or ##J_i##.
 
ilvpat said:
When you say Xi is 1 if sibling is member of a pair, do you mean a pair of opposite sex? And does it mean both bro and sis in ith pair got assigned to another pair of opposite sex?

sorry, I left something out,, I meant if the sibling is paired with someone of the opposite sex.
 
You should think the other way to solve this question, first consider choosing 10 persons, calculate each case from 1 male to 10, then for each case, the possibilities to have siblings or couples pair. Using excel sheet can easily get the answer.
 
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