- #1
chopasticks
- 2
- 0
how can i proof that >>>>>> p(A | B') = p(A | B)
well i tried but i think there is a hole in the solution T.T
if we said that
p(A|B)=p(A&B)/p(B)
p(A|B')= p(A&B')/p(b')
= p(A) - p(A&B)/1-p(B)
so0o0o how can i complete it ??
well i tried but i think there is a hole in the solution T.T
if we said that
p(A|B)=p(A&B)/p(B)
p(A|B')= p(A&B')/p(b')
= p(A) - p(A&B)/1-p(B)
so0o0o how can i complete it ??