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this is the problem:

solve the expression for n Є N

P(2n + 4, 3) = 2/3P(n+4, 4)

this is my work:

(2n +4)!/(n-3)! = (2/3(n+4)!)/(n-4)!

-2(n-2)!/(n-3)! = -2/3(n-4)!/(n-4)!

-2/(n-3)! = -2/3

-2 = -2/3(n-3)

-2 = -2n/3 +6/3

-2 = -2n/3 +2

-6 = -2n +2

-8 = -2n

n=4

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# Probability solve the expression P(2n+4,3) = 2/3P(n+4,4) for n

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