Problem concerning a mass with charge in a homogeneous electric field

AI Thread Summary
The discussion centers on the confusion regarding the relationship between electric force and net force for charged droplets in a homogeneous electric field. While the droplets fall at a constant velocity, indicating zero net force, this does not imply that the electric field is zero. The electric field is determined by the electric force acting on the charge, not the net force. The key distinction is that the electric force is one component of the total forces acting on the droplet, which includes gravitational force. Understanding this difference clarifies the reasoning behind the presence of an electric field despite the absence of net force.
youmei0426
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Homework Statement
As stated in the photo
Relevant Equations
For a homogenous field: E=F/q
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I know how the answer is C, since E=F/q and F=ma=mg. However, I am a bit confused as to why my other method doesn't work. I thought that since the droplets are falling at a constant velocity, there is not net force, so according to E=F/q the electric field must be zero then? This seems like a really weird way of thinking but I can't tell what exactly went wrong in my reasoning... Thanks for the help!
 
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youmei0426 said:
I thought that since the droplets are falling at a constant velocity, there is not net force, so according to E=F/q the electric field must be zero then?

Your first line is correct, since the droplets are falling at constant velocity the net force is zero. So think about the second equation, ##E = \frac F q##. In this equation, what is F?
 
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youmei0426 said:
I thought that since the droplets are falling at a constant velocity, there is not net force,
That is correct.
youmei0426 said:
... so according to E=F/q the electric field must be zero then?
That is not correct. There is a difference between F and Fnet. The F in E = F/q is the electric force not the net force. Fnet is the sum of all the forces acting on the droplet.
 
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