Problem in Gama function;can you answer soon.

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The discussion centers on proving a property of the Gamma function, specifically that Gamma(1/2) equals the square root of pi. The relationship Gamma(x + 1) = x * Gamma(x) is highlighted as a key tool for the proof. It is noted that the negative signs encountered during calculations lead to alternating signs in the results. The proof can be approached through mathematical induction on integer values of m. Overall, the conversation emphasizes the importance of these relationships in deriving properties of the Gamma function.
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Hello i am very happy to sent my firest question,so i am very happy from forum.
my problem is : prove that
right&space;)^{m}2^{m}\sqrt{\pi&space;}}{1.3.5....\left&space;(&space;2m-1&space;\right&space;)}.gif

using
gif.gif



I try by:
let
gif.gif
 

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  • right&space;)^{m}2^{m}\sqrt{\pi&space;}}{1.3.5....\left&space;(&space;2m-1&space;\right&space;)}.gif
    right&space;)^{m}2^{m}\sqrt{\pi&space;}}{1.3.5....\left&space;(&space;2m-1&space;\right&space;)}.gif
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quantum220 said:
Hello i am very happy to sent my firest question,so i am very happy from forum.
my problem is :
prove that
right&space;)^{m}2^{m}\sqrt{\pi&space;}}{1.3.5....\left&space;(&space;2m-1&space;\right&space;)}.gif

The pi term comes from the fact that Gamma(1/2) = SQRT(pi). The rest you can deduce from using the relationship Gamma(x + 1) = x * Gamma(x). Basically because they are negative you are going to get switching signs since every step is multiplying by a negative number and the rest can be obtained from the definition. (I'm assuming m is an integer of course)
 
If m= 0, that says that \Gamma(1/2)= \sqrt{\pi} which is true.

Now, use \Gamma(x+ 1)= x\Gamma(x)to prove the rest by induction on m.
 
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