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Problem in graph of Quadratic Equation

  1. Aug 28, 2005 #1
    Hey, could someone please help me with this problem? I just want to know why the graph of Quadratic Equation are symmetric and why does the maxima and minima ( = -b/2a ) the mean of the two roots? One more thing I didn't get was what does the a represent in ax2+bx+c ( ax square+bx+c)? I know for b and c, but couldn't figure out for a? Is it for the slope or whether the graph will be > 0 or < 0?
  2. jcsd
  3. Aug 28, 2005 #2


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    If you write [itex]ax^2+bx+c[/itex] in the more 'insightful' form:


    You can see that it is equal to the graph of [itex]ax^2[/itex], but shifted vertically by [itex]c-\frac{b^2}{4a}[/itex] and horizontally by [itex]\frac{b}{2a}[/itex]. The a can be seen as a scaling factor in the y-direction. If it's positive, you have a 'dale-parabola', if it's negative it's a 'hill-parabola'.
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