Problem in understanding the concept of acceleration due to gravity?

AI Thread Summary
Acceleration due to gravity is consistently 9.81 m/s² for objects falling from heights that are a small fraction of Earth's radius. This value remains uniform because the gravitational field does not change measurably at such heights. In low Earth orbit, the gravitational field is slightly weaker but still close to this value. The gravitational force decreases at an inverse square rate, dropping to g/4 at a distance equal to the Earth's radius. Understanding these principles clarifies that acceleration due to gravity remains constant under typical conditions.
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This question may sound quite stupid but I am having a hard time understanding acceleration due to gravity.
When a ball falls down from a specific height. Would its acceleration always even from the start be 9.8 m/s^2 or would it say initially be a different number and then come down to 9.8?
 
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Always 9.81 m/sec/sec.
 
Acceleration will be the same, numerically, as the g field. If the height the object is dropped from is a small fraction of the radius of Earth then the acceleration will be uniform because the gravitational field will not change measurably. There is very little change, even, for objects in low Earth orbit but the field drops off at an inverse square rate. So, it will be g/4 when you get to a height equal to the Earth's radius - i.e twice as far away from the centre as you are on the surface. That's a long way away, though.
 
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