Problem Involving The Conservation Of Energy

AI Thread Summary
The discussion revolves around a physics problem involving a child sliding down a water slide, focusing on the conservation of energy. The mechanical energy at the top of the slide is correctly calculated as 1704 J. The confusion arises in determining the height of the slide above its bottom, where the child is 2.5 meters above the water level. The correct interpretation is that the height of the slide above the bottom is the difference between the total height of 3.36 meters and the 2.5 meters above the water, leading to the realization that the height of the slide itself is only 0.86 meters. The participant expresses gratitude for the clarification after initially misunderstanding the question.
Pat2666
Messages
33
Reaction score
0
I have another problem I need some help with.

Here's the problem :

A 51.1 kg child slides down a water slide with a velocity of 0.9 m/sec at the top. At the bottom of the slide, she is moving horizontally, y=2.5 meters above the water. She splashes into the water d=3 meters to the left of the bottom of the slide.
--------------------------------------------------------------------------------
a) Assuming potential energy to be zero at the water level, what is the mechanical energy of the child at the top of the slide?
MEo= J
1704 J
--------------------------------------------------------------------------------
b) How high is the top of the slide above the bottom of the slide?

As shown I was able to find out the mechanical energy of the child at the top of the slide (1704J) but I can't seem to figure out how to solve for the height of the slide.

I would have thought that you just set KE + PE = 1704 and solve for h, which I did and got 3.36m, but it isn't the right answer :(

So I did .5(51.1kg)(.9m/s)^2 + 51.1kg(9.81m/s^2)h = 1704J

I'm stumped as I don't see any other way of solved for the height. Any help would be appriciated. :)
 
Physics news on Phys.org
Hi Pat2666,

The potential energy is zero at the water's surface, so that's where h=0 at. So when you found that h=3.36m, that means the slide is that far above the water's surface.

However, although that will help to answer part b, that's not quite what part b was asking for.
 
Well it's not really asking for the total height is it? Just the height of the top of the slide to the end of it no? I tried adding 3.36m to the 2.5m above water just to see if I misread the question, but it was still wrong.
 
The top of the slide is 3.36 m above the water, the bottom of the slide is 2.5 meters above the water. The question is asking for how far the top of the slide is above the bottom of the slide. What would that be?
 
OMG I'm so dumb! Thank you lol

I kept thinking that what I was solving for was h, rather than h + the additional height.

Thanks so much! I've been working on this problem forever!
 
Sure, glad to help!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top