Problem of Oscillation of mass attached to spring with external force

AI Thread Summary
The discussion focuses on a mass-spring system experiencing forced oscillation due to an external force proportional to cos ωt, where ω is not equal to the natural angular frequency ω0. The governing equations include F = -kx and F = -mω²x, which describe the system's behavior. The solution involves combining the natural frequency dynamics with the external force's influence. Participants suggest referencing textbooks on oscillation or acoustics for deeper insights into forced oscillation problems. Understanding the time displacement of the oscillator requires analyzing the interaction between the spring force and the external force.
Saurabh Sikchi
Messages
1
Reaction score
0

Homework Statement


A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ω0. An external force. F(t) proportional to cos ωt(ω ≠ ω0) is applied to the oscillator. The time displacement of the oscillator will be?


Homework Equations


F=-kx
=-mω2x


The Attempt at a Solution


F=-ω02x+F0cos ωt
 
Physics news on Phys.org
This is the problem of forced oscillation you can get it in any book on oscillation or acoustics
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top