Problem on finding second derivative.

[jzq]

I have a problem on finding the second derivative for this function:

\frac {x}{x^2-4}

For the first derivative, I got:

\frac {-x^2-4}{(x^2-4)^2}

Now here is where I am stuck! So far for the second derivative, I got this (Please check!):

\frac {-2x(x^2-4)^2-4x(-x^2-4)(x^2-4)}{(x^2-4)^4}

I need the second derivative simplified! I know, it's an easy question. I may have lost my mind!
Also please explain. Thanks!

BTW. I am new to this forum and just learned the latex system. It is very complicated. Took me a while just to write out the problems above. I guess I got to get used to it.

 

[Davorak]

Those look good to me. Now all you need to do is simplify. That should be the easy step. You have a factor of (x^2-4) that will divide out. You should be able to get it down to one term.

 

[jzq]

Those look good to me. Now all you need to do is simplify. That should be the easy step. You have a factor of (x^2-4) that will divide out. You should be able to get it down to one term.

Is this what you got?:

\frac {2x^3+24x}{(x^2-4)^3} or \frac {2x(x^2+12)}{(x^2-4)^3}

 

[Davorak]

Looks good