# Problem on tangents to a cirlce

Suppose we have a cirlce with diameter AB.P and Q are points on opposite sides of te diameter(both points are on the circumference).Now PR=QM where R and M are also on opposite sides and on the same sides of P and Q outside the circle.

Now if we draw tangents from R and M,how do we prove that they will be equal in length?

We basically have to prove $$RL=MG$$ taking $$RP =QM$$

if L and G are the contact points

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mathman
Your assumption is that RP=QM. Let C be the center. First RC=MC, since you are adding radii to the known pieces sticking out. Next, LC=GC (both radii). Therefore you have two right triangles with hypotenuses equal, and also equality in one leg. Therefore the other leg pair (RL and MG) are also equal.

This looks like an elementary geometry exercise.

But P and Q and C arent necessarily collinear

uart
anantchowdhary, you haven't fully specified the problem. What is the direction of PR and QM? Are they both radial, or are they both perpendicular to AB or are they something else.

they arent radial and they arent parallel to each other.we just know that
RP=QM

uart
they arent radial and they arent parallel to each other.we just know that
RP=QM

Then RL and MG certainly need not be equal

RL and MG will be equal only
when if the lines RP and QM produced intersect the same diamter necessarily

uart