(glass/2)=?
- 2
- 0
Hello All,
I can compute the solution, but I fail to see how it further simplifies into the final expression. The solution manual lists both the answer and its simplified formulation.
How do I go from step three to step four?
Find the derivative of: f(x) = (2x)^{\sqrt{2}}
\frac{d}{dx}x^{r}=r^{r-1}
1) f(x) = (2x)^{\sqrt{2}} = (2^{\sqrt{2}})(x^{\sqrt{2}})
2) Application of the product rule: g'(x)f(x) + f'(x)g(x)
3) Answer = 2^{\sqrt{2}}\sqrt{2}x^{\sqrt{2}-1}
4) Simplification: 2\sqrt{2}(2x)^{\sqrt{2}-1}
Many Thanks!
I can compute the solution, but I fail to see how it further simplifies into the final expression. The solution manual lists both the answer and its simplified formulation.
How do I go from step three to step four?
Homework Statement
Find the derivative of: f(x) = (2x)^{\sqrt{2}}
Homework Equations
\frac{d}{dx}x^{r}=r^{r-1}
The Attempt at a Solution
1) f(x) = (2x)^{\sqrt{2}} = (2^{\sqrt{2}})(x^{\sqrt{2}})
2) Application of the product rule: g'(x)f(x) + f'(x)g(x)
3) Answer = 2^{\sqrt{2}}\sqrt{2}x^{\sqrt{2}-1}
4) Simplification: 2\sqrt{2}(2x)^{\sqrt{2}-1}
Many Thanks!