Problem to understand how the power is distributed

  • Thread starter Thread starter Lorens
  • Start date Start date
  • Tags Tags
    Distributed Power
AI Thread Summary
The discussion revolves around understanding power distribution in a static scenario involving a wheel. The original poster is attempting to calculate the resultant force at a 45-degree angle, estimating it to be around 3920 N. Participants clarify that since the system is static, the power is effectively zero, as nothing is in motion. The conversation emphasizes the importance of recognizing that static conditions imply no power output. Overall, the key takeaway is that in a static situation, power distribution is not applicable.
Lorens
Messages
29
Reaction score
0
I can’t get in the picture below which power I will get on the wheel, i am guessing that there will be an resultant on 45 degree with a force of around400*9,82 N.

http://img33.imageshack.us/img33/2695/problemhjul4rh.jpg
Thx for any help given
 
Last edited by a moderator:
Physics news on Phys.org
So there are no missunderstandings

http://img475.imageshack.us/img475/723/problemhjul27vf.png
 
Last edited by a moderator:
Can you clarify the question?
 
How will the power be distributed at the wheel?
 
The power is zero, isn't it? Nothing is moving. It's a statics question?
 
berkeman said:
The power is zero, isn't it? Nothing is moving. It's a statics question?

Yes it's static :smile: ...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top