- #1

Loopas

- 55

- 0

I've attached a screenshot of this particular question. I was able to figure out part A but I'm having some difficulty with part B.

T = I*alpha

I = .5mr^2 (for a solid cylinder like the grinding wheel)

F = ma

I've gotten as far as setting up the equation and solving for Tf.

(T1-T2)(r) - Tf = (.5)(m)(r)(a)

So Tf = (T1-T2)(r) - (.5)(m)(r)(a)

Which gives me .01878 Nm, which rounds to .019 Nm.

For the acceleration, I've been using .28/6.7 = .04179 m/s^2

**Relevant equations:**

T = I*alpha

I = .5mr^2 (for a solid cylinder like the grinding wheel)

F = ma

**Attempt at solution:**

I've gotten as far as setting up the equation and solving for Tf.

(T1-T2)(r) - Tf = (.5)(m)(r)(a)

So Tf = (T1-T2)(r) - (.5)(m)(r)(a)

Which gives me .01878 Nm, which rounds to .019 Nm.

For the acceleration, I've been using .28/6.7 = .04179 m/s^2