Problem with this estimation lemma example

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Discussion Overview

The discussion revolves around evaluating the limit of an integral involving a complex function, specifically the expression $$\lim_{U\rightarrow\infty}\int_C \frac{ze^{ikz}}{z^2+a^2}dz$$ where the contour C is defined in the complex plane. Participants explore various approaches to this problem, including the use of the residue theorem and properties of the integrand.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant attempts to show the limit of the integral and uses the modulus of the integrand to bound the integral.
  • Another participant questions the description of the contour C and points out the presence of poles at $$ia$$ and $$-ia$$, suggesting the use of the residue theorem.
  • Several participants provide inequalities involving the integrand, specifically focusing on the term $$|e^{ikz}|=e^{-kU}$$ and its implications for the integral's evaluation.
  • There is a mention of the condition that if neither pole is inside the contour C, the integral evaluates to zero due to analyticity.

Areas of Agreement / Disagreement

Participants express differing views on the approach to take for evaluating the integral, with some focusing on the residue theorem while others emphasize bounding the integrand. The discussion remains unresolved as multiple competing methods are proposed without consensus on the best approach.

Contextual Notes

Participants note specific conditions regarding the contour and the location of poles, which may affect the evaluation of the integral. There are also references to assumptions about the behavior of the integrand as $$U$$ approaches infinity.

Who May Find This Useful

This discussion may be useful for those studying complex analysis, particularly in the context of contour integration and the residue theorem, as well as for individuals interested in the evaluation of limits involving complex integrals.

Jenny short
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I have been trying to show that

$$\lim_{U\rightarrow\infty}\int_C \frac{ze^{ikz}}{z^2+a^2}dz = 0 $$

Where $$R>2a$$ and $$k>0$$ And C is the curve, defined by $$C = {x+iU | -R\le x\le R}$$

I have tried by using the fact that

$$|\int_C \frac{ze^{ikz}}{z^2+a^2}dz| \le\int_C |\frac{ze^{ikz}}{z^2+a^2}|
|dz|$$

I want to use the fact $$|e^{ikz}|=e^{-kU}$$

However I got really stuck after that. I would really appreciate help
 
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I do not understand your description of the curve C. Anyhow, z^{2}+a^{2}=(z-ia)(z+ia), so you have poles in ia and -ia. The residue at ia is \frac{iae^{-ka}}{2ia}=\frac{e^{-ka}}{2}. Now you just have to calculate the other residue and use the residue theorem...
 
Last edited:
|\frac{ze^{ikx}}{z^2+a^2}|\leq e^{-kU}|\frac{z}{z^2+a^2}|

Does that help?
 
mathman said:
|\frac{ze^{ikx}}{z^2+a^2}|\leq e^{-kU}|\frac{z}{z^2+a^2}|

Does that help?
I've done that, but I'm suck on what to do after that
 
To continue what I said above: As long as C is given by \vert z\vert=R with R>\vert a \vert, the value of the integral is given by 2\pi i\sum Res_{\vert z \vert <R}.
 
Last edited:
More information: If neither ia or -ia is inside C, then the function is analytic there, thus the integral must be 0.
 

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