Problem with two review problems

  • Thread starter Thread starter maverick99
  • Start date Start date
  • Tags Tags
    Review
AI Thread Summary
The discussion revolves around solving two geometry problems: finding the perimeter of an isosceles triangle with base angles of 36 degrees and an area of 580 cm², and determining the dimensions of a rectangular workbench that is four times as long as it is wide. Participants emphasize the importance of understanding the properties of isosceles triangles, clarifying that the angles must sum to 180 degrees, which leads to the correct calculation of the triangle's dimensions. The formula for the area of the triangle is discussed, with suggestions to start from basic principles. The conversation highlights the need for participants to engage with the problems actively rather than seeking direct answers.
maverick99
Messages
74
Reaction score
0
First of all, thanks for anyone who helps me with this

1. Find the perimeter of an Isoceles triangle that has base angles of 36 degrees and an area of 580cm sq.
The given answer is 126.4cm.

2. A designer plan the top of a rectangular workbench to be four times as long as it is wide, and then determines that if the width is 2.5 ft greater and the length is 4.7ft less, it wouldbe a square. What are its dimensions?
 
Physics news on Phys.org
maverick99 said:
First of all, thanks for anyone who helps me with this

1. Find the perimeter of an Isoceles triangle that has base angles of 36 degrees and an area of 580cm sq.
The given answer is 126.4cm.

2. A designer plan the top of a rectangular workbench to be four times as long as it is wide, and then determines that if the width is 2.5 ft greater and the length is 4.7ft less, it wouldbe a square. What are its dimensions?

1.& 2.What have you done so far?The problems are not difficult,and therefore it's better that u did them yourself,maybe with some help from us.Post your work.

Daniel.
 
dextercioby said:
1.& 2.What have you done so far?The problems are not difficult,and therefore it's better that u did them yourself,maybe with some help from us.Post your work.

Daniel.

I just need help starting both of them, that's all.
 
Well - what's the formula in getting the area of the triangle??
You should start off with that.
 
futb0l said:
Well - what's the formula in getting the area of the triangle??
You should start off with that.

well i know that its 1/2(b)(h) but i don't know what it means by 2 base angles of 36 degrees. Since it's isocoles, doesn't it have a right angle, therefore 36+36+90=162 which it should add up to 180
 
maverick99 said:
well i know that its 1/2(b)(h) but i don't know what it means by 2 base angles of 36 degrees. Since it's isocoles, doesn't it have a right angle, therefore 36+36+90=162 which it should add up to 180

I doubt the original problem was formulated with a triangle on a saddle (negative total curvature),but in a plane,so those angles should add up to 180°.
U'll find more useful this formula:
S_{triangle}=\frac{1}{2}l_{1}l_{2} \sin \alpha
,where \alpha is the angle between those 2 sides l_1 and l_2.

Daniel.
 
isosceles doesn't mean right angle it's just
36+36+ 108 = 180
 

Similar threads

Back
Top