Problems computing area with integrals.

haydn
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Homework Statement



Find the total area enclosed by the graphs of

y=9x^2–x^3+x
y=x^2+16x


Homework Equations



No real equations, just using integrals

The Attempt at a Solution



I graph the functions and find they intersect at 0 and 5, and that y=x^2+16x seems to be the upper function while y=9x^2-x^3+x is the lower function.

I set up an integral with the lower limit 0 and the upper limit 5, and x^2+16x - (9x^2-x^3+x) dx inside the integral.

I solve by simplifying and using the fundamental theorem of calculus and get 10.416. The homework website I'm using is telling me this is wrong...

Thank you.
 
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They intersect at three points, not two. One is a cubic equation. Can you find them?
 
Last edited:
I've checked it which sage and I get 10.416... I say forget what the website says.
 
Nevermind. Follow Dick's advice.
 
Dick said:
They intersect at three points, not two. One is a cubic equation. Can you find them?

Found it and got the correct answer. Thanks a bunch!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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