1. The problem statement, all variables and given/known data Find the total area enclosed by the graphs of y=9x^2–x^3+x y=x^2+16x 2. Relevant equations No real equations, just using integrals 3. The attempt at a solution I graph the functions and find they intersect at 0 and 5, and that y=x^2+16x seems to be the upper function while y=9x^2-x^3+x is the lower function. I set up an integral with the lower limit 0 and the upper limit 5, and x^2+16x - (9x^2-x^3+x) dx inside the integral. I solve by simplifying and using the fundamental theorem of calculus and get 10.416. The homework website I'm using is telling me this is wrong... Thank you.