Projectile Equation Help: Finding Velocity for Water Thrown at 60 Degrees

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Homework Help Overview

The problem involves determining the initial velocity required for water to hit a flower located 5 meters away, thrown at an angle of 60 degrees from the horizontal. The scenario assumes no air resistance and that the water is thrown from the same vertical level as the flower.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of parametric equations for projectile motion and the need to separate horizontal and vertical components. Questions arise about finding the time variable and how to relate it to the initial velocity.

Discussion Status

Some participants have provided guidance on breaking down the motion into components and using standard equations of motion. Others are exploring different approaches to find the time and initial velocity, with ongoing attempts to verify calculations and reasoning.

Contextual Notes

There is mention of the problem not being from a textbook with solutions, which may contribute to uncertainty in the participants' approaches. Additionally, the original poster expresses urgency for assistance.

reisada
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english is not my native language , ill do my best

Homework Statement


someone wants to throw water to a flower that is to the distance of 5 m and at the same level as the place where the water comes from. air resistance doesn't count

what is the velociity of the water so that it hits the flower, if the water is thrown with an angle of 60 degrees from the horizontal?


Homework Equations





The Attempt at a Solution




already put the parametric equations of the movement :
x=xo + voxt
y=yo+voyt-1/2gt^2
but now i can't do anithing else!

and i can't find any way to find the velocity of the water( the inicial one i think)

anione can help fast please? thanks a lot
 
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Are you able to write down the equations of motion for a projectile in terms of s, u, v and t?
These are the standard equations one uses to solve such problems
If you can do this, then you need to be able to split the motion into horizontal and vertical components and solve from there.
Let me know how much of that made sense
 


well first of all let me repost :D

the parametric equations are :
x=vo*costeta*t
and
y=vo*sinteta-5t^2

then when vo*costeta*t=5, , when 5 is the reach, we can find the vo
vo=5/0.5t

but now how can i find the time for this equation? am i going well?
 


aha , now ill try to do the position/time which is:

r(t)= vocostetat ex + vosintetat - 5t^2 ey

now if i find the zeros of this function i can get the time right?EDIT : damn this way i still don't know the vo...
 


ok so i restarted the exercise and now i got an answer, can you guys please try to see if this is the correct answer? because this exercise is not from any book with solutions

so this is what i did:
x=vocos60t
y=vosin60t+5t^2

vosin60t+5t^2=0 ( when it is vertically at the same spot as the flower)
t=0 and t= 0,173vo

then

x=vocos60*t
0,5vo*0,173vo = 5 (when x is 5, i calculated the vo)
vo = 7,6 m/s



what was your answer please answer this is really making my mind go crazy :D thanks in advance
 

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