Projectile locust jump question

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Locusts can jump up to 75 cm on a level surface, with an entomologist noting their launch angle at 55 degrees. To determine the initial velocity, one can break it down into x and y velocity components using trigonometric functions. The horizontal distance can be described by the formula for projectile motion, which incorporates the initial velocity and time of flight. The time of flight can be calculated from the initial y velocity and the constant acceleration due to gravity. Understanding these principles will help in solving for the initial velocity of the locust.
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Large insects such as Locusts can jump as far as 75 cm. on a level surface. an entomologist analyzed a photograph and found that the insects's launch was at an angle of 55.
What was the initial velocity of the insect?

those are the only givens I am given... how do i figure this one out? Even a small hint would be appreciated :-D
 
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Having the initial angle is quite a lot. From that you can identify the initial x and y velocity components. That is a good place to start.

What formula can describe the distance observed in the x direction? And how might you calculate the time of flight from initial y velocity and knowing gravity acts at a constant rate?
 

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