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Projectile Motion #2

  1. Oct 25, 2006 #1
    A rocket is launched at an angle of 57.0° above the horizontal with an initial speed of 96 m/s. It moves for 3.00 s along its initial line of motion with an acceleration of 30.0 m/s^2. At this time its engines fail and the rocket proceeds to move as a free body.

    (a) Find the maximum altitude reached by the rocket.
    (b) Find its total time of flight.
    (c) Find its horizontal range.

    I tried finding \Delta X using

    \Delta X = Vo^2/g2sin(theta)

    I got 120.8117 for X

    then i plugged it in Delta X = Vo X sin 2a / g
  2. jcsd
  3. Oct 25, 2006 #2

    my message is too short so i am typing this to make it longer.
  4. Oct 25, 2006 #3

    Go back and look at the formula's I gave you on the first problem with the cliff. They should be all you need.

    Max altitude is when y velocity is zero. Total flight time is when y location is zero. That will give you the flight time, plug that time into the x location formula and you are done.

  5. Oct 25, 2006 #4
    I think it's a little trickier than that. Kilders, here's a hint: during the first 3 seconds, the motion is linear (what can you deduce from that?), and then the rocket proceeds as a projectile (the final velocity of the linear motion is the initial velocity of the projectile).

    Hope this helps. Ask if you need further clarification.
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