- #51

gneill

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Gneill when i use the quadratic form, and plug in the given variables i do not get 1.27 or 1.23 or anywhere near that

∆t = [-2.86+/- sqrt( -2.86^2-4(4.906)(-4)]/(2(4.906) )

t=-3.8 or -1.91

The 'b

^{2}' term inside the square root should not be negative. The 'c' term is not negative in this case, it's the initial height which is positive.

Initial height is +4m. Final height is 0.00m (ground).

The kinematic equation in the vertical direction is

[itex] 0 = h + v_y t - \frac{1}{2}g t^2 [/itex]