Projectile motion at an angle problem

AI Thread Summary
A ball is thrown at a 40-degree angle with an initial velocity of 28 m/s, and the problem seeks to determine the horizontal distance it travels before hitting the ground. The vertical component of the initial velocity (Vyo) is calculated as 18 m/s, and the horizontal component (Vxo) is 21.4 m/s. The total time of flight can be found using the equation Ttotal = (2Vyo)/g, where g is the acceleration due to gravity. The horizontal distance can then be calculated using the formula X = Vi*t + (1/2)At^2, where A is zero for horizontal motion. Clarification on the next steps and equations is requested to resolve the confusion.
Anton338
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Homework Statement


A ball is thrown at a 40 degree angle from the horizontal over level ground. If the initial velocity of the ball is 28 meters per second, how far does the ball travel before hitting the ground?

Homework Equations


X=Vi*t+(1/2)At^2
Ttotal=(2Vyo)/g
sine/cosine/tangent
A^2+B^2=C^2

The Attempt at a Solution


Vyo = 18m/s because Sin(40)*28
Vxo = 21.4m/s because Cos(40)*28

aaand I'm stuck. What do I need? Where do I go?
SO CONFUSED :P

Thanks Forum
 
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