Projectile motion, Cat jumping off table

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SUMMARY

The discussion centers on calculating the time a cat takes to jump off a table using projectile motion equations. The user derived the time using the formula \( t = \frac{Vi \sin \theta - \sqrt{(Vi^2 \sin^2 \theta + 2gh)}}{g} \), but received feedback indicating a discrepancy in the sign of the expression. The correct approach emphasizes that the negative sign in the square root should be treated as positive, ensuring accurate time calculation in projectile motion scenarios.

PREREQUISITES
  • Understanding of basic physics concepts related to projectile motion
  • Familiarity with kinematic equations, specifically \( 0 = Xi + Vit + \frac{1}{2}a(t^2) \)
  • Knowledge of trigonometric functions, particularly sine and cosine
  • Ability to manipulate algebraic expressions and solve quadratic equations
NEXT STEPS
  • Study the derivation of projectile motion equations in detail
  • Learn how to apply kinematic equations to different projectile scenarios
  • Explore the effects of varying launch angles on projectile distance
  • Investigate real-world applications of projectile motion in sports and engineering
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in understanding the dynamics of objects in motion.

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Homework Statement


A cat jumps off of the table with a velocity vi at an angle θ. The table is h meters tall. How far away from the table is the cat?
V(x) = ViCosθ
V(y) = ViSinθ

Homework Equations


I first solved for time using 0 = Xi + Vit +1/2a(t^2)

The Attempt at a Solution


I got time as
t = ViSinθ-√(Vi2Sinθ2 + 2gh) / g But my teacher got a answer slightly different. Am I solving for time the write why? I think so. If not, What am I missing? Thanks
 
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The negative sign should be positive in the expression of t.
 

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