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## Homework Statement

A cat jumps off of the table with a velocity vi at an angle θ. The table is h meters tall. How far away from the table is the cat?

V(x) = ViCosθ

V(y) = ViSinθ

## Homework Equations

I first solved for time using 0 = Xi + Vit +1/2a(t^2)

## The Attempt at a Solution

I got time as

t = V

_{i}Sinθ-√(V

_{i}

^{2}Sinθ

^{2}+ 2gh) / g

But my teacher got a answer slightly different. Am I solving for time the write why? I think so. If not, What am I missing? Thanks