Projectile motion flight time of ball

AI Thread Summary
To find the flight time of a ball thrown at an angle, the equation t = (2 v0 sin theta)/g is used. The initial velocity v0 is derived from the relationship involving the height H and gravitational acceleration g, leading to the equation (v0 sin theta)^2 = 2gH. The challenge arises when trying to eliminate the variable R from the calculations, as the problem specifies that only H and g should remain. By substituting the expression for (v0 sin theta) into the flight time equation, the solution can be simplified. Ultimately, the focus is on expressing flight time solely in terms of H and g.
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[SOLVED] Projectile motion

Homework Statement




A ball is thrown with an intial velocity of v0 at an angle theta from the horizontal. Find the flight time of the ball in terms of H and g only.

Homework Equations


t = (2 v0 sin theta)/g

The Attempt at a Solution



Ok. I found theta to be the tan inverse of 4R/H. Thus, the initial velocity is sqrt[Rg/sin(2tan-1(4R/H))] - a little longwinded but accurate. However, my problem arises when I plug these values into the above equation and those really nasty 'R's refuse to go away, and the problem specifically states that g and H should be my only variables. I feel like i must be missing something really obvious, and if so, i apologise in advance, but please help anyway! Thank you!
 
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When the ball reaches the height H, its velocity is equal to zero. So using kinametics equation we get (vosin theta)^2 = 2gH. From this equation find the value of (v0sin theta) and plug it the relevant equation.
 
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