a ball is fired from a cannon at an angle of 40 degrees to the horizontal and it travels 300m before hitting the side of a cliff which is 10 meters higher than the cannons position. Determine the initial velocity. The ball has a negative velocity when it hits the cliff. My attempt: Where v = the balls initial velocity y component of velocity = -9.81t + Vsin40 integrate this and get y position = .5*-9.8t^2 + vsin40t x component of velocity = vcos40 integrate this and get x position = vcos40t Using the expression for x velocity, solve for t at 300m in the x direction and get the expression t=300/vcos40 Sub this into the expression for the y position above and solve for v. I'm unsure if this is the correct way to go about doing this. The velocity I ended up with is 42.7124ms^-1 which seems a bit slow for the distance it covers.