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Projectile motion of long jump

  1. Oct 13, 2009 #1
    1. The problem statement, all variables and given/known data
    During a high school track meet, an athlete performing the long jump runs and leaps at an angle of 25 degrees and lands in a sand pit 8.8 m from his launching point. If the launch point and landing point are at the same height, y=0m, with what apeed does the athlete land?



    2. Relevant equations



    3. The attempt at a solution
    Im completely stumped. any help would be appreciated.
     
  2. jcsd
  3. Oct 13, 2009 #2
    Are you familiar with the range formula?
     
  4. Oct 13, 2009 #3
    no i am not.
     
  5. Oct 13, 2009 #4
    can anyone tell me what the range formula is?
     
  6. Oct 13, 2009 #5
    R = ((v0)2 sin(2[tex]\theta[/tex]0)) / g

    Rearranging this formula and solving for v0 will give you the initial velocity. You can figure out the final velocity from there.
     
  7. Oct 13, 2009 #6
    well then how do i find initial velocity to put it in.
     
  8. Oct 13, 2009 #7
    i didnt see the second part of that. sorry. thank you
     
  9. Oct 13, 2009 #8
    im having trouble with this. i keep getting initial velocity as a decimal
     
  10. Oct 13, 2009 #9
    Maybe you aren't substituting/manipulating properly.

    [tex] x = \frac{v_o^2sin2\theta}{g}[/tex]
    [tex]v_o=\sqrt{\frac{xg}{sin2\theta}}[/tex]
     
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