A diver leaves the springboard with a vertical velocity of 5.7m/s, and horizontal velocity of 1.2 m/s, and a height of 3.49m. How long will it take her to return to the same height? What horizontal range will she cover in this time?(adsbygoogle = window.adsbygoogle || []).push({});

Would I use: Time = 2Vvert/g for the first part? And Range = (Vhor)(Time) for the second part?

MY ANSWERS:

1st part --> Time = 1.16 s

2nd part --> Range = 1.4 m

Is this correct?

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# Projectile Motion Q

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