Projectile Motion (Regular Physics) question

AI Thread Summary
To determine how far the ball lands from the table after rolling off a ramp, first calculate the ball's speed at the end of the ramp and the angle of projection using trigonometry. The vertical and horizontal components of the initial velocity can be derived from the ramp's angle, with the vertical component aiding in calculating the time the ball is in the air. The time in the air, combined with the horizontal velocity, allows for the calculation of the horizontal distance traveled. The angle of the ramp does affect the final speed, and the equations of motion can be applied to find the necessary values. Understanding these components is crucial for accurately positioning the cup to catch the ball.
Jonathen
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Homework Statement


A ball was let go at the top of a ramp 15 cm. high and 70.5 cm long it then goes to drop off the end of a 92 cm. table after it leaves the ramp how far will the ball land from the table. This is for a general physics class so neglect air resistance and use 10.0 m/s^2 for gravity, I am not sure if you need to use angles we have not used them before and this was a actual lab in which we had to land the ball into a cup, we had to position the cup meaning we needed to know where the ball would land. Thank You.


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Calculate the speed of the ball at the end of the ramp and also the angle at which it is projected from the table. Calculate the vertical and horizontal components of the initial velocity, and then use these to find the time that the ball is in the air for and therefore the distance it travels horizontally.
 
Will the angle of the ramp effect how fast it is going at the end of the ramp? if not will Vf=Vo+a(t) work? if it does how would I calculate the angle at which the ball is launched OFF OF THE TABLE? Thank you for replying so quickly.
 
You can find the angle at which it is launched off the table by using trigonometry to find the rightmost angle in the ramp. Ill call this angle \theta.

The horizontal component of the velocity will be u_x=u\:cos(\theta) and the vertical component will be u_y = u\:sin(\theta) downwards. Given that you know the height of the ramp from the floor, you can use the vertical velocity to find the time before it hits the floor. You can then use this time with u_x to find how far horizontally it travels.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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