Projectile motion snowball help

In summary, projectile motion is the curved path an object follows through the air due to the influence of gravity and external forces. The distance traveled by a snowball thrown at an angle can be calculated using the equation d = v0 * cos(theta) * t. The maximum height reached by a snowball can be calculated using the equation h = (v0 * sin(theta))^2 / (2 * g). Air resistance can slow down and alter the trajectory of a snowball, affecting its motion. Factors such as air resistance, wind, surface conditions, and the shape and weight of the snowball can all impact the accuracy of projectile motion calculations.
  • #1
imAwinner
10
0
[SOLVED] Projectile motion help

A snowball rolls of a barn roof that slopes downward at an angle of 40 degrees. The edge of the roof is 14 m above the ground, and the snowball has a speed of 7 m/s as it rolls off the roof.

a) How far from the edge of the barn does the snowball strike the ground if it doesn't strike anything else while falling?

b) A man 1.9 m tall is standing 4 m from the edge of the barn, will he be hit by the snowball?

My answer is 11.792 m for (a)

x
a=0
v=7cos40=5.36
x=5.36t


y
a=-9.8
v=7sin40-9.8t= 4.5-9.8t
y=4.5t-4.9t^2+14 (is this right?)

When y=0 : 0=-4.9t^2 + 4.5t + 14 (use quadratic equation)
t=2.2
Plug it into x equation: x=5.36(2.2)
x=11.792 m

Now for (b) i don't know what to do. I said x=4 and got t=.746 s
Then I plugged it into the y equation but my answer turned out to be 14.36 which is impossible. Any help is greatly appreciated.
 
Last edited:
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  • #2
Your equation for x-axis is correct. However, in the equations along y axis, the initial velocity should be with -ve sign (-4.5 m/s) because it is downward (same reason acceleration g is -ve). As the snowball hits the ground, vertical displacement is -14m (note the -ve sign). Put y=-14 in the second equation and solve for t. Put this value of t in the equation for x to obtain the required distance from the edge of the barn.

To find answer to b) : Determine the time instant when horizontal displacement is 4m. Then determine the vertical displacement (from the top) at that instant. Determine height of the snowball from ground. That will answer b).
 
  • #3
Vijay Bhatnagar said:
Your equation for x-axis is correct. However, in the equations along y axis, the initial velocity should be with -ve sign (-4.5 m/s) because it is downward (same reason acceleration g is -ve). As the snowball hits the ground, vertical displacement is -14m (note the -ve sign). Put y=-14 in the second equation and solve for t. Put this value of t in the equation for x to obtain the required distance from the edge of the barn.

To find answer to b) : Determine the time instant when horizontal displacement is 4m. Then determine the vertical displacement (from the top) at that instant. Determine height of the snowball from ground. That will answer b).

Thank you but shouldn't y still equal zero because the y and x-axis is on the bottom of the barn not the roof; even though its traveling negative it hits at zero, not -14?

Never mind, its the same thing. Thank you so much!
 
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  • #4
The choice of the origin is optional. You could take the top point as y=0 or the ground as y=0. In the first case initial displacement will be 0 and final displacement -14m. In the second case initial and final displacements will be +14m and 0 respectively. All equations for y-axis will written accordingly.
 

What is projectile motion?

Projectile motion is the motion of an object through the air that is influenced by gravity and any other external forces acting on it. It follows a curved path known as a parabola.

How do you calculate the distance traveled by a snowball thrown at an angle?

The distance traveled by a snowball can be calculated using the equation: d = v0 * cos(theta) * t, where v0 is the initial velocity, theta is the angle of projection, and t is the time the snowball is in the air.

What is the maximum height reached by a snowball thrown at an angle?

The maximum height reached by a snowball can be calculated using the equation: h = (v0 * sin(theta))^2 / (2 * g), where v0 is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity.

How does air resistance affect the motion of a snowball?

Air resistance can affect the motion of a snowball by slowing it down and altering its trajectory. This is because air resistance acts in the opposite direction of the motion of the snowball, causing it to lose speed and change direction.

What factors can affect the accuracy of projectile motion calculations for a snowball?

The accuracy of projectile motion calculations for a snowball can be affected by factors such as air resistance, wind, and the surface the snowball is thrown on. Other factors such as the shape and weight of the snowball can also impact the accuracy of the calculations.

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