Projectile Motion, Vector Component Confusion

AI Thread Summary
A projectile is launched at a 45-degree angle with an initial velocity of 300 m/s, resulting in horizontal and vertical components of 212 m/s each. The vertical displacement at the peak is calculated to be 2293 m using the kinematic equation vf^2 = vi^2 + 2a(d) with final velocity at the peak being zero. To find the total time the projectile is in the air, the equation dy = vi(t) + 1/2 a(t)^2 is applied, but confusion arises regarding the correct calculation. The vertical velocity at half the time is zero, allowing for the use of Vy = Viy + at to determine the time. The discussion highlights the need for clarity in applying kinematic equations to solve for time in projectile motion.
cire792
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Homework Statement



Canon fired at 45Degrees, at 300m/s
Assuming no air resistance,
a= -9.8m/s^2
ViX = 300cos45 = 212m/s
ViY = 300sin45 - 212m/s
Displacement = 2293m [used vf^2=vi^2+2a(d)] rearranged for d, and vf=0, at highest peak.

Time the ball is in the air= ?

Homework Equations



Thinking I have to use this, but this is where my math skills are rusty.

dy = vi (t) + 1/2 a(t)^2

The Attempt at a Solution



time = -1038
 
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You noted that Vy = 0 at half time.
So you can use Vy = Viy + at to find the half time. Viy = 212
 
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