Projectile Motion velocity and direction

AI Thread Summary
The discussion focuses on solving a projectile motion problem where a projectile is launched at 20 m/s at a 40° angle and strikes a non-linear ground surface described by the equation y = 0.4x – 0.006x². Key points include determining the coordinates of the impact point, the projectile's velocity and direction upon impact, its highest point in flight, and the maximum height achieved. Participants express confusion regarding the non-constant ground function, especially compared to simpler flat ground scenarios. The conversation highlights the importance of correctly applying horizontal and vertical motion equations to find the intersection of the projectile's trajectory with the ground. Overall, the thread emphasizes the complexities introduced by a variable ground surface in projectile motion calculations.
aaronfue
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Homework Statement



At t = 0, a projectile is located at the origin and has a velocity of 20 m/s at 40° above the horizontal. The profile of the ground surface it strikes can be approximated by the equation y = 0.4x – 0.006x2, where x and y are in meters. Determine (a) the approximate coordinates of the point where it hits the ground, (b) its velocity and direction when it hits the ground, (c) its highest point in flight and (d) the greatest distance above the ground.

Homework Equations



vo= 20 \frac{m}{s}
θ=40°
Horizontal Motion: x=xo2 + (vo)x2t + \frac{1}{2}at
Vertical Motion: y=yo2 + (vo)y2t + \frac{1}{2}at

The Attempt at a Solution



This function of the ground is confusing me. I'm not sure where to start with this.
 

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When you do one of these problems with a flat ground you also have do deal with a function that describes the height of the ground at a given distance, but it is easy since the function is constant. Here you do the same thing, but you have a non-constant function for the ground. In both cases you find the place where the trajectory intersects the ground.
 
aaronfue said:
Horizontal Motion: x=xo2 + (vo)x2t + \frac{1}{2}at
Vertical Motion: y=yo2 + (vo)y2t + \frac{1}{2}at
The powers of 2 are in the wrong places.
 
haruspex said:
The powers of 2 are in the wrong places.

Got it. Thanks!
 
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