Projectile motion with aerodynamic drag force

AI Thread Summary
The discussion revolves around a projectile motion problem involving a mass of 1300kg launched with initial velocity components of 108m/s, while experiencing aerodynamic drag. The user attempts to calculate the drag force and its components but struggles with the numerical methods required to solve the equations of motion. It is noted that the problem cannot be solved analytically and requires numerical solutions using Newton's second law. The user questions whether to post in a more advanced physics section, indicating uncertainty about their current understanding. The conversation emphasizes the complexity of the problem and the necessity of applying differential equations for accurate results.
IceD
Messages
2
Reaction score
0

Homework Statement



A projectile of mass 1300kg is launched from the ground (x =0, y =0)
initial velocity components Vx=Vy=108m/s
aerodynamic drag force is of magnitude C(V)^2
where C = 0.6

Homework Equations



Finding the range and angular momentum initial and final


The Attempt at a Solution


1. I found V = 152.74 (*by V= root(Vx^2 + Vy^2)
2. and weight as 12753 kg
3. I tried to find aerodynamic drag force (FD), but I got something like 13997.70 m^2/s^2
(it should be in Newtons right?)
4. I think I'll break FD to x and y components and use them to calculate when it'll reach it's peak (Vy= 0) and based on it I'll use the the t to get the distance...but how to find it?
5. for the angle, can I assume that it was 45 degrees angle?
since Vx=Vy?
6. and I have no idea how to find the angular momentum @.@

Sorry if my working is quiet "useless" cause I'm quiet "blind" at this subject...

Thanks before :D

Regards,
IceD
 
Physics news on Phys.org
This question is not a trivial one and indeed, cannot be solved analytically in terms of elementary functions. You can however, solve the system numerically.

As you say, you need to apply Newton's second law to each component (horizontal and vertical) of the motion. This will then yield a system of two coupled differential equations that you will need to sole numerically.

As I said, this problem isn't straightforward and the fact that you have posted this in the Introductory Physics forums would suggest that you are still in elementary physics classes. So I must as, are you sure that you have the question correct? How much numerical analysis have you done?
 
yes, I'm sure that the question is correct @.@
I found the V and the W... but can't go any further than that @.@
huff...
so should I post this question in advance physics section?
 
IceD said:
yes, I'm sure that the question is correct @.@
I found the V and the W... but can't go any further than that @.@
huff...
so should I post this question in advance physics section?
Have you tried to write down the two PDEs from Newton's Second law?

I think that your question is fine here, but I can move it for you if you wish.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

The motion of a skateboarder along and above a ramp
Replies
2
Views
562
Projectile Motion Problem Involving Initial Velocity and Gravity Only
Replies
11
Views
1K
Projectile Motion velocity vector Problem
Replies
2
Views
2K
Final Velocity of a car with a opposing decreasing drag force
2
Replies
57
Views
2K
Find the height of a lamp based on the velocities of projectiles
Replies
40
Views
2K
2D equation for projectile with linear drag force
Replies
9
Views
3K
Projectile Motion: Solving for Distance with Integration
Replies
1
Views
3K
Uniform Circular Motion and Projectile Motion Help
Replies
14
Views
2K
Motion of a Parachuter (Terminal Velocity, Time of Flight, Distance)
Replies
10
Views
1K
Is the y-component of projectile motion acceleration equal to gravity?
Replies
8
Views
2K

Hot Threads

Recent Insights

Back
Top