Calculating Horizontal Speed of a Stealth Bomber

[jamesc3]

a stealth bomber on a training mission drops one of its bombs from a height of 3500m during level flight. The bomb travels a horizontal distance of 1.25 km. What was the plane's horizontal speed?



a brick is thrown upward from the top of a building at an angle of 25 degrees to the horizontal and with an initial speed of 15 m/s. it strikes the ground below. if teh brick is in flight for 3.0 s, how tall is the building?


i don't know the equation or the answer, can someone provide both for me?

 

[redargon]

read the rules about homework questions and try again.

hint: the projectile motion equations are usually found under kinematic equations or just kinematics.

 

[tomcue]

Sure, I can help you with both problems.

For the first one, to calculate the horizontal speed of the stealth bomber, we can use the formula for horizontal distance: d = v*t, where d is the horizontal distance, v is the horizontal speed, and t is the time. We know that the bomb travels 1.25 km (or 1250 m) in 3.0 seconds, so we can plug in these values and solve for v:

1250 m = v * 3.0 s
v = 1250 m / 3.0 s
v = 416.67 m/s

Therefore, the horizontal speed of the stealth bomber is approximately 416.67 m/s.

For the second problem, we can use the formula for vertical displacement: h = v0*t + 0.5*a*t^2, where h is the height, v0 is the initial vertical velocity, a is the acceleration due to gravity (9.8 m/s^2), and t is the time. We know that the brick is in flight for 3.0 seconds and that it starts with an initial vertical velocity of 15 m/s. We also know that the brick lands on the ground, so its final height is 0.

0 = 15 m/s * 3.0 s + 0.5 * 9.8 m/s^2 * (3.0 s)^2
0 = 45 m + 44.1 m
h = -89.1 m

Since the height cannot be negative, we must take the absolute value of h, so the building is approximately 89.1 meters tall.

I hope this helps! Remember, when solving problems like these, it's important to use the appropriate equations and units, and to carefully consider the given information.